i thought of starting with a random picture,so that the math blog wont be so mathy >:P
Today pic :D
this is a pretty picture ^.^,it makes me feel like i'm in a spy movie:)
well on today's math blog our aim today is:(tan-tan-tan)
How do we Factor by grouping?
when we factor a equation, we use the cubic equation
like:
2x3+ 4x2+25x+10= 0
because this equation is a cubic equation we cannot use the diamond problem to find the factors.
lets get started :
Step 1: we separate this equation in half like : 2x3+4x2
Step 2: we find the greatest common factor of 2x3+4x2.
in this case 2x2 is their common factor,because both 2 and 4 are divisible by 2 and both of them have x's.
Step 3: using the common factor we can make a factor of 2x3+4x2
for example:
2x3+4x2 (original part)
2x2(x+2) (undistributed part )
Step 4: then we find the common factor of the second part of the equation.
For example: 25x+10
5(x+2)
5 = the greatest common factor
(x+2)= is the factor of 25x+10
Step5: connect the parts together.
2x2(x+2) + 5(x+2)
Step 6: finishing up by grouping it.
For example:
2x2(x+2) + 5(x+2)
(2x2+5) = connect both the 2x2+5 into one parenthesis.
(x+2)= stays the same.
Final answer:
(2x2+5)(x+2)
Now you try :
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LAST PICTURE:
This is how I feel after doing math blogs :)
Problems: http://www.regentsprep.org/Regents/math/algtrig/ATV1/RevFactPractice.htm
First Picture: http://cdn.c.photoshelter.com/img-get/I0000XMSl1tB.tzg/s/650/650/jiufen-taiwan-chinese-lanterns-night-002.jpg
Last picture:http://www.regentsprep.org/Regents/math/algtrig/ATV1/revFactorGrouping.htm
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