I'm a bit late..well i'm really late because of some technical difficulties:(.
so lets get started with a math-christmas photo since its CHRISTMAS!!
and like a total nerd im doing a blog xP
oh well, here the picture:
I dont know if HO3, is a chemistry component or a math picture but what ever I think the bear is super dupper cute
>.<.
now that the picture is over, we are going to solve the question of the day :
How do we simply expressions with rational exponents?
so lets start with a simple, and easy expression like:
x4
x-6because we cannot have a negative exponent in the bottom of the bar we have to switch the negative exponent along with the x and flip it to the opposite side.
For example:
given expression :
x4
x-6change the negative exponent to the opposite side of the bar. Therefore:
x4 x6
1from there,we can say we are multiplying both x's. when we multiply, the exponents are added therefore :
x4x6 : 4+6
x10
lets try more problems:
x3x(2/4)x-3 =
Step one : add all exponents
3+(2/4)+(-3)
3+(-3) =0
0+(2/4) = (2/4)
Step two : combine the answers
X(2/4)
Another problem:
(X15 Y25 )(1/5)
Step one: first multiply the outside exponent to the inside exponents.
(X15 Y25 )(1/5) :
(15)(1/5)
multiply straight across so it would be :
X: 15 x 1 = 15 = 3
1 5 5
Y: 25 x 1 = 25 = 5
1 5 5
Step Two: combine the exponents to its appropriate variable.
X3Y5
NOW YOU TRY :D
X-3
X2
X (-9/18)
X3
Works cited :
picture : http://i1.cpcache.com/product/180766012/ho_ho_ho_christmas_math_humor_teddy_bear.jpg?height=150&width=150
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